Identify the aromatic compound.

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(C) compound is aromatic if it follows $H$ückel's rule ($4n+2$ $\pi$ electrons),is planar,and cyclic.$A$: Cyclopentadienone has $4$ $\pi$ electrons in

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$2-$aminopyridin$-4-$one

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(C) compound is aromatic if it follows $H$ückel's rule ($4n+2$ $\pi$ electrons),is planar,and cyclic.$A$: Cyclopentadienone has $4$ $\pi$ electrons in the ring (anti-aromatic).$B$: Cycloheptatriene has an $sp^3$ hybridized carbon atom,so it is not planar and not aromatic.$C$: $2-$aminopyridin$-4-$one is a tautomer of $2-$amino$-4-$hydroxypyridine. The ring is planar,fully conjugated,and contains $6$ $\pi$ electrons ($4$ from double bonds + $2$ from the lone pair on the nitrogen atom in the ring),satisfying $H$ückel's rule $(n=1)$. Thus,it is aromatic.$D$: The structure shown is not aromatic due to the presence of $sp^3$ hybridized nitrogen and lack of continuous conjugation.

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