Identify the complex which exhibits optical i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Optical isomerism is exhibited by complexes that lack a plane of symmetry and a center of symmetry (chiral complexes).For octahedral complexes of

Vedclass · Accepted Answer

$[Co(en)_3]Cl_3$

Vedclass · Answer

(C) Optical isomerism is exhibited by complexes that lack a plane of symmetry and a center of symmetry (chiral complexes).For octahedral complexes of the type $[M(AA)_3]$,where $AA$ is a bidentate ligand like ethylenediamine $(en)$,the complex exists as a pair of enantiomers (non-superimposable mirror images).In the given options,$[Co(en)_3]Cl_3$ contains three bidentate ligands,which creates a chiral environment around the central metal ion,thus exhibiting optical isomerism.The other complexes listed are either of the type $[MA_5B]$ or $[MA_4BC]$,which generally exhibit geometrical isomerism but not optical isomerism.

Identify the complex which exhibits optical isomerism.

Similar Questions

The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is $2$. The metal ion is

How many geometrical isomers and stereoisomers are possible for $[Pt(NO_2)(NH_3)(NH_2OH)(Py)]^+$ and $[Pt(Br)(Cl)(I)(NO_2)(NH_3)(Py)]$ respectively?

How many isomeric forms will the complex ion $[Co(NH_3)_4Cl_2]^+$ exhibit?

Which among the following elements in their respective oxidation states develops the lowest spin-only magnetic moment? (Atomic numbers: $Cu=29, Fe=26, Ni=28, Co=27$)

In the coordination complex $[CoF_6]^{3-}$,the number of unpaired electrons is equal to ......

Vedclass Test Series

Exam Paper Generator

Online Exam Module