Identify the conjugate acid-base pair respect | vedclass

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(A) conjugate acid-base pair differs by only one proton $(H^{+})$.In the reaction: $HPO_4^{2-} + H_2O \rightleftharpoons PO_4^{3-} + H_3O^{+}$$1$. $HP

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$H_3O^{+}$ and $H_2O$

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(A) conjugate acid-base pair differs by only one proton $(H^{+})$.In the reaction: $HPO_4^{2-} + H_2O \rightleftharpoons PO_4^{3-} + H_3O^{+}$$1$. $HPO_4^{2-}$ acts as an acid and loses a proton to form its conjugate base,$PO_4^{3-}$. Thus,$(HPO_4^{2-}, PO_4^{3-})$ is a conjugate acid-base pair.$2$. $H_2O$ acts as a base and gains a proton to form its conjugate acid,$H_3O^{+}$. Thus,$(H_3O^{+}, H_2O)$ is a conjugate acid-base pair.Comparing this with the given options,$H_3O^{+}$ and $H_2O$ represent a conjugate acid-base pair.

Identify the conjugate acid-base pair respectively from the following equilibrium reaction.
$HPO_{4(aq)}^{2-} + H_2O_{(\ell)} \rightleftharpoons PO_{4(aq)}^{3-} + H_3O_{(aq)}^{+}$

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Identify the conjugate acid-base pair respectively from the following equilibrium reaction.$HPO_{4(aq)}^{2-} + H_2O_{(\ell)} \rightleftharpoons PO_{4(aq)}^{3-} + H_3O_{(aq)}^{+}$