Identify the correct observation with respect | vedclass

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(B) For the first graph ($p$ vs $1/V$): According to the ideal gas equation $pV = nRT$, we have $p = (nRT) 	imes (1/V)$. The slope of the line is $nR

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$T_2 > T_1$ and $p_1 > p_2$

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(B) For the first graph ($p$ vs $1/V$): According to the ideal gas equation $pV = nRT$, we have $p = (nRT) 	imes (1/V)$. The slope of the line is $nRT$. Since the slope for $T_2$ is greater than the slope for $T_1$, it follows that $T_2 > T_1$.For the second graph ($V$ vs $T$): According to Charles' law $V = (nR/p) 	imes T$. The slope of the line is $nR/p$. Since the slope for $p_2$ is greater than the slope for $p_1$, and the slope is inversely proportional to pressure, it follows that $p_1 > p_2$.Therefore, the correct observation is $T_2 > T_1$ and $p_1 > p_2$.

List-$I$	List-$II$
$(1)$ Boyle's Law	$(A)$ $p \propto T$
$(2)$ Charles's Law	$(B)$ $V \propto n$
$(3)$ Gay-Lussac's Law	$(C)$ $p \propto \frac{1}{V}$
$(4)$ Avogadro's Law	$(D)$ $pV = nRT$
$(5)$ Ideal Gas Equation	$(E)$ $V = k_2T$

Identify the correct observation with respect to the given graphs.

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