Identify the correct option regarding the dis | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Option $(B)$ is correct. $PhCHO$ (Benzaldehyde) does not contain an $\alpha$-methyl group,so it does not give a positive Tollen's test for silver

Vedclass · Accepted Answer

Pair of compounds: $(I) PhCHO, (II) CH_3CHO$. Reagent: Tollen's reagent $(AgNO_3 + NH_4OH)$. Response: $(II)$ forms a silver mirror,$(I)$ does not.

Vedclass · Answer

(B) Option $(B)$ is correct. $PhCHO$ (Benzaldehyde) does not contain an $\alpha$-methyl group,so it does not give a positive Tollen's test for silver mirror formation in the same way as aliphatic aldehydes,but more importantly,$CH_3CHO$ (Acetaldehyde) is an aliphatic aldehyde that readily reduces Tollen's reagent to form a silver mirror. Option $(A)$ is incorrect because $HCHO$ does not have an $\alpha$-methyl group and does not give the iodoform test,while $CH_3CHO$ does. Option $(C)$ is incorrect because both glucose and fructose react with bromine water (fructose isomerizes to glucose in basic/neutral conditions or reacts via enediol). Option $(D)$ is incorrect because $2,4-DNP$ reacts with all carbonyl compounds (aldehydes and ketones),so it cannot distinguish between them.

Identify the correct option regarding the distinction between pairs of compounds.

Similar Questions

Which of the following reactions does not represent the aldol condensation reaction?

Which of the following is Clemmensen reduction?

Cyclohexylamine when treated with nitrous acid yields $(P)$. On treating $(P)$ with $PCC$ results in $(Q)$. When $(Q)$ is heated with dilute $NaOH$,we get $(R)$. The final product $(R)$ is:

When acetaldehyde is reacted with $LiAlH_4$,what is the product formed?

During the reaction of benzaldehyde with alkali,one of the products is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module