Identify the correct trend given below.(Atomi | vedclass

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(C) The crystal field splitting energy $(\Delta _0)$ is directly proportional to the oxidation state of the central metal ion. $A$ higher oxidation st

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$\Delta _0$ of $[Cr(H_2O)_6]^{2+}  [Ti(H_2O)_6]^{2+}$

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(C) The crystal field splitting energy $(\Delta _0)$ is directly proportional to the oxidation state of the central metal ion. $A$ higher oxidation state results in a greater electrostatic attraction between the ligands and the metal,leading to larger splitting.Therefore,$\Delta _0$ of $[Ti(H_2O)_6]^{3+} > \Delta _0$ of $[Ti(H_2O)_6]^{2+}$.Additionally,$\Delta _0$ increases down a group because the $4d$ orbitals are more extended than $3d$ orbitals,leading to stronger interaction with ligands. Thus,$\Delta _0$ of $[Mo(H_2O)_6]^{2+} > \Delta _0$ of $[Cr(H_2O)_6]^{2+}$.Combining these,the correct trend is $\Delta _0$ of $[Cr(H_2O)_6]^{2+}  [Ti(H_2O)_6]^{2+}$.

Identify the correct trend given below.
(Atomic No. $= Ti : 22, Cr : 24$ and $Mo : 42$)

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Identify the correct trend given below.(Atomic No. $= Ti : 22, Cr : 24$ and $Mo : 42$)