Identify the incorrect statement about the ox | vedclass

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Question

(C) In group $14$, the stability of the $+2$ oxidation state increases down the group due to the inert pair effect. Therefore, $Pb^{2+}$ is the most s

Vedclass · Accepted Answer

Lead in $+2$ oxidation state is a reducing agent.

Vedclass · Answer

(C) In group $14$, the stability of the $+2$ oxidation state increases down the group due to the inert pair effect. Therefore, $Pb^{2+}$ is the most stable state for lead. Consequently, $Pb^{2+}$ acts as an oxidizing agent because it tends to gain electrons to reach the more stable $Pb^0$ state or remain in the $Pb^{2+}$ state, whereas $Sn^{2+}$ acts as a reducing agent because it tends to lose electrons to reach the more stable $Sn^{4+}$ state. Thus, the statement that lead in $+2$ oxidation state is a reducing agent is incorrect.

List-$I$	List-$II$
$A$. Coke	$I$. Carbon atoms are $sp^3$ hybridised
$B$. Diamond	$II$. Used as a dry lubricant
$C$. Fullerene	$III$. Used as a reducing agent
$D$. Graphite	$IV$. Cage like molecules

Identify the incorrect statement about the oxidation states of group $14$ elements.

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Match List-$I$ with List-$II$.

List-$I$ List-$II$

$A$. Coke $I$. Carbon atoms are $sp^3$ hybridised

$B$. Diamond $II$. Used as a dry lubricant

$C$. Fullerene $III$. Used as a reducing agent

$D$. Graphite $IV$. Cage like molecules

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Which ions are present in aluminosilicates?

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