Identify the logic gate from the following wi | vedclass

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(D) The given circuit consists of two $NAND$ gates acting as $NOT$ gates (since their inputs are shorted) followed by a $NAND$ gate. Let the inputs be

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$OR$

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(D) The given circuit consists of two $NAND$ gates acting as $NOT$ gates (since their inputs are shorted) followed by a $NAND$ gate. Let the inputs be $A$ and $B$. The first two $NAND$ gates invert the inputs to produce $\bar{A}$ and $\bar{B}$. The final $NAND$ gate takes these as inputs, so the output $Y$ is given by $Y = \overline{\bar{A} \cdot \bar{B}}$. Using De Morgan's theorem, $\overline{\bar{A} \cdot \bar{B}} = \overline{\bar{A}} + \overline{\bar{B}} = A + B$. This is the Boolean expression for an $OR$ gate. Therefore, the circuit behaves as an $OR$ gate.

Identify the logic gate from the following with the same truth table characteristics as the logic circuit shown below.

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