Identify the major product formed in the brom | vedclass

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(D) The bromination of $2-$methylpropane proceeds via a free radical mechanism. In the propagation step,a hydrogen atom is abstracted from the alkane

Vedclass · Accepted Answer

$2-$Bromo$-2-$methylpropane

Vedclass · Answer

(D) The bromination of $2-$methylpropane proceeds via a free radical mechanism. In the propagation step,a hydrogen atom is abstracted from the alkane to form an alkyl radical. The abstraction of a hydrogen atom from the tertiary carbon atom leads to the formation of a $3^{\circ}$ alkyl radical,while abstraction from a primary carbon atom leads to a $1^{\circ}$ alkyl radical. Since the $3^{\circ}$ alkyl radical is more stable than the $1^{\circ}$ alkyl radical due to hyperconjugation and inductive effects,the reaction proceeds primarily through the $3^{\circ}$ radical intermediate. Consequently,$2-$bromo$-2-$methylpropane is the major product.

Identify the major product formed in the bromination of $2-$methylpropane.

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