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Question

(C) The Clemmensen reduction uses zinc-amalgam $(Zn-Hg)$ and concentrated hydrochloric acid $(HCl)$ to reduce carbonyl groups $(C=O)$ of aldehydes and

Vedclass · Accepted Answer

$1-$chloro$-3-$ethyl$-5-$methylcyclohexane

Vedclass · Answer

(C) The Clemmensen reduction uses zinc-amalgam $(Zn-Hg)$ and concentrated hydrochloric acid $(HCl)$ to reduce carbonyl groups $(C=O)$ of aldehydes and ketones to methylene groups $(CH_2)$.Additionally,under these acidic conditions,secondary and tertiary alcohols can undergo substitution reactions with $HCl$ to form alkyl chlorides.In the given molecule,the ketone group is reduced to an ethyl group $(-CH_2CH_3)$,and the secondary alcohol group is converted into a chloro group $(-Cl)$.Therefore,the major product is $1$-chloro-$3$-ethyl-$5$-methylcyclohexane.

Identify the major product of the following reaction:

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Identify the major product of the following reaction:

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When ethanal $(CH_3CHO)$ and propanal $(CH_3CH_2CHO)$ undergo cross-aldol condensation with dilute $NaOH$, the pair of products obtained by cross-condensation reaction is:

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In the given reaction :
$CH_3CHO$ $\xrightarrow[(i) \ NaCN/HCl]{(ii) \ H_2O/H^{\oplus}/\Delta} (A)$ $\xrightarrow[reagent]{Fenton} (B)$
$(B)$ will be :