Identify the number of unpaired electrons pre | vedclass

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(D) For the complex $[Co(NH_3)_6]^{3+}$:$1$. The oxidation state of $Co$ is $+3$.$2$. The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6 4s^0$.$3

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$0$,octahedral

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(D) For the complex $[Co(NH_3)_6]^{3+}$:$1$. The oxidation state of $Co$ is $+3$.$2$. The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6 4s^0$.$3$. $NH_3$ is a strong field ligand,which causes pairing of electrons in the $3d$ orbitals.$4$. After pairing,all $6$ electrons occupy the first three $3d$ orbitals,leaving no unpaired electrons $(n = 0)$.$5$. The complex undergoes $d^2sp^3$ hybridization,resulting in an octahedral geometry.

Identify the number of unpaired electrons present and the geometry of the $[Co(NH_3)_6]^{3+}$ complex,respectively.

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