Identify the optically active compound from t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) An optically active compound must be chiral,meaning it lacks a plane of symmetry or a center of symmetry. In the complex $[Co(en)_3]Cl_3$,the liga

Vedclass · Accepted Answer

$[Co(en)_3]Cl_3$

Vedclass · Answer

(C) An optically active compound must be chiral,meaning it lacks a plane of symmetry or a center of symmetry. In the complex $[Co(en)_3]Cl_3$,the ligand $en$ (ethylenediamine) is a bidentate ligand. The complex $[Co(en)_3]^{3+}$ forms a tris-chelated octahedral structure that does not possess a plane of symmetry or a center of symmetry. Therefore,it exists as a pair of non-superimposable mirror images (enantiomers),making it optically active. The other complexes listed are either square planar or octahedral with planes of symmetry,rendering them optically inactive.

Identify the optically active compound from the following.

Similar Questions

The spin magnetic moment of cobalt in the compound $Hg[Co(SCN)_4]$ is (in $B.M.$)

Which of the following predictions is correct when a transition metal ion is colourless?

Which of the following complex species is not expected to exhibit optical isomerism?

Which of the following square planar complex molecular formulas exhibits $cis-trans$ isomerism? ($a$ and $b$ are monodentate ligands)

Among $Ni(CO)_4$,$[Ni(CN)_4]^{2-}$,and $[NiCl_4]^{2-}$,which of the following statements is correct regarding their magnetic properties?

Vedclass Test Series

Exam Paper Generator

Online Exam Module