Identify the organic compounds $P$, $Q$, and $R$ in the following reaction sequence: $C_3H_6 \xrightarrow[ii) H_2O_2/NaOH]{i) BH_3} P \xrightarrow[anhydrous medium]{CrO_3} Q \xrightarrow[ii) H_3O^+]{i) CH_3MgBr} R + Mg(OH)Br$.

  • A
    $P = H_3C-CH(OH)-CH_3, Q = H_3C-C(=O)-CH_3, R = H_3C-C(OH)(CH_3)_2$
  • B
    $P = H_3C-CH_2-CH_2-OH, Q = H_3C-CH_2-CHO, R = H_3C-CH_2-CH(OH)-CH_3$
  • C
    $P = H_3C-CH_2-CH_2-OH, Q = H_3C-CH_2-COOH, R = H_3C-CH_2-C(=O)-OCH_3$
  • D
    $P = H_3C-CH(OH)-CH_3, Q = H_3C-C(=O)-CH_3, R = H_3C-CH(OCH_3)-CH_3$

Explore More

Similar Questions

Benzaldehyde can be converted to benzyl alcohol in concentrated aqueous $NaOH$ solution using

When acetaldehyde is heated with Fehling's solution,it gives a red precipitate of:

Which of the following compounds does not react with concentrated alkali to give the corresponding alcohol and salt of carboxylic acid?

Arrange the following compounds in the increasing order of their equilibrium constants for the formation of a hydrate:
$(I)$ $6$-amino-$1$-tetralone
$(II)$ $7$-amino-$1$-tetralone
$(III)$ $1$-tetralone
$(IV)$ $6$-nitro-$1$-tetralone

Propyne was subjected to a reaction with $HgSO_4/dil. H_2SO_4$,which resulted in a product $P$. The product $P$ was heated with $Ba(OH)_2$ to give the product $Q$. The molecular formula of the product $Q$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo