Identify the product B in the following serie | vedclass

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(B) Step $1$: The reaction between $CH_3COOH$ and $CH_3CH_2OH$ in the presence of $H^{+}$ is an esterification reaction,which produces ethyl acetate $

Vedclass · Accepted Answer

$CH_3CH_2OH$

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(B) Step $1$: The reaction between $CH_3COOH$ and $CH_3CH_2OH$ in the presence of $H^{+}$ is an esterification reaction,which produces ethyl acetate $(A)$ as the product.
$CH_3COOH + CH_3CH_2OH \rightleftharpoons[H^{+}]{H^{+}} CH_3COOCH_2CH_3 (A) + H_2O$
Step $2$: The reduction of an ester $(A)$ using $H_2/Ni, \Delta$ leads to the formation of alcohols.
$CH_3COOCH_2CH_3 + 2H_2 \xrightarrow{Ni, \Delta} CH_3CH_2OH + CH_3CH_2OH$
Thus,the product $B$ is $CH_3CH_2OH$ (ethanol).

Identify the product $B$ in the following series of reaction.
$CH_3COOH + CH_3CH_2OH \rightleftharpoons{H^{+}} CH_3COOCH_2CH_3{_{\text{(A)}}} \xrightarrow[Ni/Pd, \Delta]{H_2} CH_3CH_2OH + CH_3CH_2OH{_{\text{(B)}}}$

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Identify the product $B$ in the following series of reaction. $CH_3COOH + CH_3CH_2OH \rightleftharpoons{H^{+}} CH_3COOCH_2CH_3{_{\text{(A)}}} \xrightarrow[Ni/Pd, \Delta]{H_2} CH_3CH_2OH + CH_3CH_2OH{_{\text{(B)}}}$