Identify the product 'B' in the following rea | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Step $1$: Reaction of $butan-2-ol$ with $PBr_3$ replaces the $-OH$ group with $-Br$ to form $2-bromobutane$ (Product '$A$').$CH_3CH_2CH(OH)CH_3 +

Vedclass · Accepted Answer

Vedclass · Answer

(C) Step $1$: Reaction of $butan-2-ol$ with $PBr_3$ replaces the $-OH$ group with $-Br$ to form $2-bromobutane$ (Product '$A$').$CH_3CH_2CH(OH)CH_3 + PBr_3 ightarrow CH_3CH_2CH(Br)CH_3 + H_3PO_3$Step $2$: Reaction of $2-bromobutane$ with $Mg$ in the presence of dry ether forms the Grignard reagent, $sec-butylmagnesium$ $bromide$ (Product '$B$').$CH_3CH_2CH(Br)CH_3 + Mg \xrightarrow{	ext{dry ether}} CH_3CH_2CH(MgBr)CH_3$The structure corresponding to $sec-butylmagnesium$ $bromide$ is given in option $C$.

Identify the product '$B$' in the following reaction sequence:
$CH_3CH_2CH(OH)CH_3 \xrightarrow{PBr_3} A \xrightarrow{Mg, \text{dry ether}} B$

Similar Questions

The order of relative reactivity of the given halides towards $S_N2$ reaction is :

The most reactive molecules towards $SN^1$ reaction are:

The major product of the following reaction is:

In $S_{N}2$ reaction,the carbon in the transition state is

Which of the following will have an enantiomer?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Identify the product '$B$' in the following reaction sequence:$CH_3CH_2CH(OH)CH_3 \xrightarrow{PBr_3} A \xrightarrow{Mg, \text{dry ether}} B$