Identify the products A and E in the followin | vedclass

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(B) $1$. The starting material is $p$-nitrotoluene. Bromination $(Br_2)$ occurs at the ortho position relative to the methyl group,yielding $A$ ($2$-b

Vedclass · Accepted Answer

$A$ = $2-$bromo$-1-$methyl$-4-$nitrobenzene,$E$ = $2-$bromobenzoic acid

Vedclass · Answer

(B) $1$. The starting material is $p$-nitrotoluene. Bromination $(Br_2)$ occurs at the ortho position relative to the methyl group,yielding $A$ ($2$-bromo-$1$-methyl-$4$-nitrobenzene).$2$. Reduction with $Sn/HCl$ converts the nitro group to an amino group,yielding $B$ ($2$-bromo-$4$-aminotoluene).$3$. Treatment with $NaNO_2/HCl$ at $273-278 \ K$ converts the amino group to a diazonium salt,yielding $C$ ($2$-bromo-$4$-methylbenzenediazonium chloride).$4$. Reduction with $H_3PO_2/H_2O$ removes the diazonium group,yielding $D$ ($2$-bromotoluene).$5$. Oxidation of the methyl group with $(i) \ KMnO_4/KOH$ followed by $(ii) \ H_3O^+$ yields $E$ ($2$-bromobenzoic acid).

Identify the products $A$ and $E$ in the following reaction sequence:

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