Identify the product formed in the following | vedclass

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(A) $LiAlH_4$ is a strong reducing agent that reduces aldehydes to primary alcohols. It does not reduce isolated carbon-carbon double bonds $(C=C)$. T

Vedclass · Accepted Answer

$CH_3-CH=CH-CH_2-CH_2-OH$

Vedclass · Answer

(A) $LiAlH_4$ is a strong reducing agent that reduces aldehydes to primary alcohols. It does not reduce isolated carbon-carbon double bonds $(C=C)$. Therefore,the aldehyde group $(-CHO)$ is reduced to a primary alcohol group $(-CH_2OH)$ while the double bond remains intact. The reaction is: $CH_3-CH=CH-CH_2-CHO \xrightarrow[(ii) \ H_3O^{+}]{(i) \ LiAlH_4} CH_3-CH=CH-CH_2-CH_2-OH$ Thus,the correct product is $CH_3-CH=CH-CH_2-CH_2-OH$.

Identify the product formed in the following reaction: $CH_3-CH=CH-CH_2-CHO \xrightarrow[(ii) \ H_3O^{+}]{(i) \ LiAlH_4} \text{Product}$

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