Identify the product obtained when benzonitri | vedclass

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(D) This reaction is known as the Stephen reduction. The reaction proceeds as follows:$1$. Benzonitrile $(C_6H_5-C \equiv N)$ is reduced by $SnCl_2$ a

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Benzaldehyde

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(D) This reaction is known as the Stephen reduction. The reaction proceeds as follows:$1$. Benzonitrile $(C_6H_5-C \equiv N)$ is reduced by $SnCl_2$ and $HCl$ to form an imine hydrochloride intermediate,benzanimine hydrochloride $(C_6H_5-CH=NH \cdot HCl)$.$2$. Subsequent acid hydrolysis $(H_3O^+)$ of the imine hydrochloride yields benzaldehyde $(C_6H_5-CHO)$ and ammonium chloride $(NH_4Cl)$.The overall reaction is: $C_6H_5-C \equiv N + 2[H]$ $\xrightarrow{SnCl_2, HCl} C_6H_5-CH=NH \cdot HCl$ $\xrightarrow{H_3O^+} C_6H_5-CHO + NH_4Cl$.

Identify the product obtained when benzonitrile is reduced by stannous chloride $(SnCl_2)$ in the presence of hydrochloric acid $(HCl)$,followed by acid hydrolysis.

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