(B) The standard electrode potential $E^\circ$ is defined for the reduction half-reaction.For the $Cu^{+2}/Cu$ electrode, the reduction reaction is th

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$Cu^{+2} + 2e^- \rightarrow Cu$

(B) The standard electrode potential $E^\circ$ is defined for the reduction half-reaction.For the $Cu^{+2}/Cu$ electrode, the reduction reaction is the gain of electrons by the copper ion to form metallic copper.The reaction is: $Cu^{+2}(aq) + 2e^- \rightarrow Cu(s)$.Thus, option $B$ represents the correct reduction reaction.

Class 12 Chemistry Electrochemistry Electrode potential and ECell

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Identify the reaction from the following that corresponds to the standard electrode potential of the $Cu^{+2}/Cu$ electrode being $0.34 \text{ V}$ with respect to the $SHE$?

MHT CET 2026 All MHT CET

A
$Cu \rightarrow Cu^{+2} + 2e^-$
B
$Cu^{+2} + 2e^- \rightarrow Cu$
C
$Cu^+ \rightarrow Cu^{+2} + e^-$
D
$Cu^{+3} \rightarrow Cu^{+2} + e^-$

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The standard reduction potential $E^{\circ}$ for half reactions are
$Zn \rightarrow Zn^{2+} + 2e^-$ $E^{\circ} = +0.76 \ V$
$Fe \rightarrow Fe^{2+} + 2e^-$ $E^{\circ} = +0.41 \ V$

The $EMF$ of the cell reaction $Fe^{2+} + Zn \rightarrow Zn^{2+} + Fe$ is

MediumWBJEE 2011

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Which of the following metals will not evolve $H_2$ gas from dilute $H_2SO_4$ solution?

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The $E^{\circ}$ of $Ce^{4+} / Ce^{3+} = 1.6 \ V$ and $Fe^{3+} / Fe^{2+} = 0.77 \ V$. The $E^{\circ}$ of the reaction where $Fe^{3+}$ oxidises $Ce^{3+}$ is:

MediumTS EAMCET 2022

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The electrode potentials are given as follows:
$Fe_{(aq)}^{3+} + e^- \to Fe_{(aq)}^{2+}$; $E^o = 0.771 \, V$
$I_{2(s)} + 2e^- \to 2I_{(aq)}^-$; $E^o = 0.536 \, V$
For the cell reaction $2Fe_{(aq)}^{3+} + 2I_{(aq)}^- \to 2Fe_{(aq)}^{2+} + I_{2(s)}$,the value of $E^o_{cell}$ is:

Medium

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$FeO_4^{2-}$ $\xrightarrow{2.0 \ V} Fe^{3+}$ $\xrightarrow{0.8 \ V} Fe^{2+}$ $\xrightarrow{-0.44 \ V} Fe^0$
In the above diagram,the standard electrode potentials are given in volts. The value of $E_{FeO_4^{2-}/Fe^{2+}}^{\Theta}$ is: (in $V$)

DifficultJEE MAIN 2025

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$Zn \rightarrow Zn^{2+} + 2e^-$	$E^{\circ} = +0.76 \ V$
$Fe \rightarrow Fe^{2+} + 2e^-$	$E^{\circ} = +0.41 \ V$

Identify the reaction from the following that corresponds to the standard electrode potential of the $Cu^{+2}/Cu$ electrode being $0.34 \text{ V}$ with respect to the $SHE$?

Similar Questions

The standard reduction potential $E^{\circ}$ for half reactions are$Zn \rightarrow Zn^{2+} + 2e^-$$E^{\circ} = +0.76 \ V$$Fe \rightarrow Fe^{2+} + 2e^-$$E^{\circ} = +0.41 \ V$The $EMF$ of the cell reaction $Fe^{2+} + Zn \rightarrow Zn^{2+} + Fe$ is

Which of the following metals will not evolve $H_2$ gas from dilute $H_2SO_4$ solution?

The $E^{\circ}$ of $Ce^{4+} / Ce^{3+} = 1.6 \ V$ and $Fe^{3+} / Fe^{2+} = 0.77 \ V$. The $E^{\circ}$ of the reaction where $Fe^{3+}$ oxidises $Ce^{3+}$ is:

The electrode potentials are given as follows:$Fe_{(aq)}^{3+} + e^- \to Fe_{(aq)}^{2+}$; $E^o = 0.771 \, V$$I_{2(s)} + 2e^- \to 2I_{(aq)}^-$; $E^o = 0.536 \, V$For the cell reaction $2Fe_{(aq)}^{3+} + 2I_{(aq)}^- \to 2Fe_{(aq)}^{2+} + I_{2(s)}$,the value of $E^o_{cell}$ is:

$FeO_4^{2-}$ $\xrightarrow{2.0 \ V} Fe^{3+}$ $\xrightarrow{0.8 \ V} Fe^{2+}$ $\xrightarrow{-0.44 \ V} Fe^0$In the above diagram,the standard electrode potentials are given in volts. The value of $E_{FeO_4^{2-}/Fe^{2+}}^{\Theta}$ is: (in $V$)

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The standard reduction potential $E^{\circ}$ for half reactions are
$Zn \rightarrow Zn^{2+} + 2e^-$ $E^{\circ} = +0.76 \ V$
$Fe \rightarrow Fe^{2+} + 2e^-$ $E^{\circ} = +0.41 \ V$

The $EMF$ of the cell reaction $Fe^{2+} + Zn \rightarrow Zn^{2+} + Fe$ is

The electrode potentials are given as follows:
$Fe_{(aq)}^{3+} + e^- \to Fe_{(aq)}^{2+}$; $E^o = 0.771 \, V$
$I_{2(s)} + 2e^- \to 2I_{(aq)}^-$; $E^o = 0.536 \, V$
For the cell reaction $2Fe_{(aq)}^{3+} + 2I_{(aq)}^- \to 2Fe_{(aq)}^{2+} + I_{2(s)}$,the value of $E^o_{cell}$ is:

$FeO_4^{2-}$ $\xrightarrow{2.0 \ V} Fe^{3+}$ $\xrightarrow{0.8 \ V} Fe^{2+}$ $\xrightarrow{-0.44 \ V} Fe^0$
In the above diagram,the standard electrode potentials are given in volts. The value of $E_{FeO_4^{2-}/Fe^{2+}}^{\Theta}$ is: (in $V$)