Identify the reducing agent in the following | vedclass

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(D) In the given reaction: $CH_{4(g)} + 2O_{2(g)} \longrightarrow CO_{2(g)} + 2H_2O_{(l)}$$1$. The oxidation state of carbon in $CH_4$ increases from

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$CH_{4(g)}$

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(D) In the given reaction: $CH_{4(g)} + 2O_{2(g)} \longrightarrow CO_{2(g)} + 2H_2O_{(l)}$$1$. The oxidation state of carbon in $CH_4$ increases from $-4$ to $+4$ (oxidation).$2$. The oxidation state of oxygen in $O_2$ decreases from $0$ to $-2$ (reduction).$3$. $A$ substance that undergoes oxidation acts as a reducing agent.$4$. Since $CH_4$ is oxidized,it is the reducing agent.

Identify the reducing agent in the following reaction:
$CH_{4(g)} + 2O_{2(g)} \longrightarrow CO_{2(g)} + 2H_2O_{(l)}$

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Identify the reducing agent in the following reaction:$CH_{4(g)} + 2O_{2(g)} \longrightarrow CO_{2(g)} + 2H_2O_{(l)}$