Identify the statement which is not correct r | vedclass

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(B) $CuSO_{4}$ reacts with $KI$ to form $Cu_{2}I_{2}$ and $I_{2}$.$CuSO_{4}$ reacts with $KCl$ to form $CuCl_{2}$ and $K_{2}SO_{4}$,not $Cu_{2}Cl_{2}$

Vedclass · Accepted Answer

It reacts with $KCl$ to give $Cu_{2}Cl_{2}$.

Vedclass · Answer

(B) $CuSO_{4}$ reacts with $KI$ to form $Cu_{2}I_{2}$ and $I_{2}$.$CuSO_{4}$ reacts with $KCl$ to form $CuCl_{2}$ and $K_{2}SO_{4}$,not $Cu_{2}Cl_{2}$.$CuSO_{4}$ reacts with $NaOH$ and glucose (a reducing agent) to form red precipitate of $Cu_{2}O$.On strong heating,$CuSO_{4}$ decomposes to form $CuO$ and $SO_{3}$.Therefore,the statement that it reacts with $KCl$ to give $Cu_{2}Cl_{2}$ is incorrect.

Identify the statement which is not correct regarding $CuSO_{4}$.

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