Identify the structure of M based on the foll | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. Compound $M$ reacts with ammoniacal $AgNO_3$ to give a white precipitate, which indicates that $M$ is a terminal alkyne $(R-C \equiv CH)$.$2$

Vedclass · Accepted Answer

$Ph-C \equiv CH$

Vedclass · Answer

(A) $1$. Compound $M$ reacts with ammoniacal $AgNO_3$ to give a white precipitate, which indicates that $M$ is a terminal alkyne $(R-C \equiv CH)$.$2$. $M$ undergoes hydrogenation with $H_2$ and Lindlar catalyst to form $N$, which is an alkene.$3$. $N$ undergoes ozonolysis to give $O$ and $P$. $O$ (benzaldehyde, $Ph-CHO$) reacts with $(CH_3CO)_2O$ and $CH_3COONa$ (Perkin's condensation) to form cinnamic acid $(Ph-CH=CH-COOH)$.$4$. Based on the reaction sequence, $M$ must be phenylacetylene $(Ph-C \equiv CH)$.$5$. $Ph-C \equiv CH + H_2 \xrightarrow{Lindlar} Ph-CH=CH_2$ $(N)$.$6$. $Ph-CH=CH_2 \xrightarrow{O_3} Ph-CHO$ $(O)$ + $HCHO$ $(P)$.$7$. Thus, $M$ is $Ph-C \equiv CH$.

Identify the structure of $M$ based on the following reaction scheme:

Similar Questions

Which alkyne will give $3$-ethylhexane on catalytic hydrogenation?

In the given reactions,find the sum of $(x + y)$.
$(1)$ $Ph-C(Br)_2-CH_3$ $\xrightarrow{xNaNH_2} (A)$ $\xrightarrow{CH_3I} Ph-C \equiv C-CH_3$
$(2)$ $CH_3-CH_2-C(Br)_2-CH_3 \xrightarrow{yNaNH_2} CH_3-C \equiv C-CH_3$
Find the value of $(x + y)$.

Which reactants are used to prepare $cis$ and $trans$ alkenes from alkynes?

The product $(B)$ of the reaction is:
$CH(CO_2H)=CH(CO_2H)$ $\xrightarrow[2 \ mole]{NaOH} (A)$ $\xrightarrow{\text{electrolysis}} (B)$

What is formed when phenylacetylene reacts with dilute $HgSO_4$ in the presence of $H_2SO_4$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module