If 1frac{1}{2} moles of oxygen combine with A | vedclass

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(B) The balanced chemical equation for the reaction is: $2Al + \frac{3}{2}O_2 	o Al_2O_3$.According to the stoichiometry of the reaction,$\frac{3}{2}

Vedclass · Accepted Answer

$54$

Vedclass · Answer

(B) The balanced chemical equation for the reaction is: $2Al + \frac{3}{2}O_2 	o Al_2O_3$.According to the stoichiometry of the reaction,$\frac{3}{2}$ moles of $O_2$ react with $2$ moles of $Al$.Given that $1\frac{1}{2}$ moles (which is $\frac{3}{2}$ moles) of $O_2$ are used,the amount of $Al$ required is $2$ moles.The molar mass of $Al$ is $27 \ g/mol$.Therefore,the weight of $Al = 2 \ mol 	imes 27 \ g/mol = 54 \ g$.

If $1\frac{1}{2}$ moles of oxygen combine with $Al$ to form $Al_2O_3$,the weight of $Al$ used in the reaction is ............. $g$ $(Al=27)$.

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