If Delta U and Delta W represent the increase | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to the first law of thermodynamics,$Q = \Delta U + \Delta W$,where $Q$ is the heat supplied to the system,$\Delta U$ is the change in in

Vedclass · Accepted Answer

$\Delta U = -\Delta W$,in an adiabatic process

Vedclass · Answer

(B) According to the first law of thermodynamics,$Q = \Delta U + \Delta W$,where $Q$ is the heat supplied to the system,$\Delta U$ is the change in internal energy,and $\Delta W$ is the work done by the system.In an adiabatic process,there is no exchange of heat between the system and the surroundings,so $Q = 0$.Substituting $Q = 0$ into the first law equation: $0 = \Delta U + \Delta W$.Rearranging the terms,we get $\Delta U = -\Delta W$.Therefore,the correct statement is that in an adiabatic process,the increase in internal energy is equal to the negative of the work done by the system.

If $\Delta U$ and $\Delta W$ represent the increase in internal energy and work done by the system respectively in a thermodynamic process,which of the following is true?

Similar Questions

Which of the following acids possesses oxidising,reducing,and complex-forming properties?

Curie temperature is the temperature above which

The product of the lengths of the perpendiculars from any point on the hyperbola $x^2 - y^2 = 8$ to its asymptotes is:

Two simple harmonic motions of angular frequency $100 \ rad \ s^{-1}$ and $1000 \ rad \ s^{-1}$ have the same displacement amplitude. The ratio of their maximum acceleration is

The points with position vectors $60i + 3j$,$40i - 8j$,and $ai - 52j$ are collinear if $a = \dots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module