If K_{sp} of Ag_2CO_3 is 8 times 10^{-12}, th | vedclass

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(C) The dissociation of $Ag_2CO_3$ is given by: $Ag_2CO_3(s) \rightleftharpoons 2Ag^+(aq) + CO_3^{2-}(aq)$.Let the solubility of $Ag_2CO_3$ in $0.1 \

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$8 	imes 10^{-10} \ M$

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(C) The dissociation of $Ag_2CO_3$ is given by: $Ag_2CO_3(s) ightleftharpoons 2Ag^+(aq) + CO_3^{2-}(aq)$.Let the solubility of $Ag_2CO_3$ in $0.1 \ M \ AgNO_3$ be $S' \ M$.The concentration of $Ag^+$ ions from $AgNO_3$ is $0.1 \ M$,and from $Ag_2CO_3$ is $2S'$.Total $[Ag^+] = (0.1 + 2S') \approx 0.1 \ M$ (since $S'$ is very small).$[CO_3^{2-}] = S'$.The solubility product expression is $K_{sp} = [Ag^+]^2 [CO_3^{2-}]$.Substituting the values: $8 	imes 10^{-12} = (0.1)^2 	imes S'$.$S' = \frac{8 	imes 10^{-12}}{0.01} = 8 	imes 10^{-10} \ M$.

If $K_{sp}$ of $Ag_2CO_3$ is $8 \times 10^{-12},$ the molar solubility of $Ag_2CO_3$ in $0.1 \ M \ AgNO_3$ is

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