If A is [Rn],6d^2,7s^2,then identify the bloc | vedclass

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(A) The electronic configuration is $A = [Rn]\,6d^2\,7s^2$.Since the last electron enters the $d-$ orbital,it belongs to the $d-$ block.The principal

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$d-$ block,$IVB, 7^{th}$ period

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(A) The electronic configuration is $A = [Rn]\,6d^2\,7s^2$.Since the last electron enters the $d-$ orbital,it belongs to the $d-$ block.The principal quantum number of the outermost shell is $n = 7$,so the period is $7$.The group number for $d-$ block elements is calculated as $(n-1)d + ns$ electrons.Here,$2 + 2 = 4$ electrons,which corresponds to group $4$ or $IVB$ in the old $IUPAC$ notation.Therefore,the element is in the $d-$ block,$IVB$ group,and $7^{th}$ period.

column-$I$ $(\text{Property})$	column-$II$ $(\text{Metal})$
$i$. An element which can show $+8$ oxidation state	$a$. $Mn$
$ii$. $3d$ series element that can show upto $+7$ oxidation state	$b$. $Cr$
$iii$. $3d$ series element with highest melting point	$c$. $Os$

If $A$ is $[Rn]\,6d^2\,7s^2$,then identify the block,period,and group.

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