If H-X bond length is 2 mathring{A} and H-X | vedclass

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(D) The theoretical dipole moment $(\mu_{Cal})$ for a $100 \%$ ionic bond is calculated as: $\mu_{Cal} = q 	imes d = (1.6 	imes 10^{-19} \ C) 	imes

Vedclass · Accepted Answer

$84$

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(D) The theoretical dipole moment $(\mu_{Cal})$ for a $100 \%$ ionic bond is calculated as: $\mu_{Cal} = q 	imes d = (1.6 	imes 10^{-19} \ C) 	imes (2 	imes 10^{-10} \ m) = 3.2 	imes 10^{-29} \ C \cdot m$. The percentage of ionic character is given by: $\% 	ext{ ionic character} = (\mu_{exp} / \mu_{Cal}) 	imes 100 = (5.12 	imes 10^{-30} / 3.2 	imes 10^{-29}) 	imes 100 = 16 \%$. The percentage of covalent character is: $\% 	ext{ covalent character} = 100 - \% 	ext{ ionic character} = 100 - 16 = 84 \%$.

If $H-X$ bond length is $2 \ \mathring{A}$ and $H-X$ has dipole moment $5.12 \times 10^{-30} \ C \cdot m$,the $\%$ of covalent character of the molecule is ............. $\%$

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