If a, b, and c are the greatest values of ^{1 | vedclass

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(D) The greatest value of $^{n}C_{r}$ is $^{n}C_{n/2}$ if $n$ is even,and $^{n}C_{(n-1)/2}$ or $^{n}C_{(n+1)/2}$ if $n$ is odd.For $a = ^{19}C_{p}$,th

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$\frac{a}{11} = \frac{b}{22} = \frac{c}{42}$

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(D) The greatest value of $^{n}C_{r}$ is $^{n}C_{n/2}$ if $n$ is even,and $^{n}C_{(n-1)/2}$ or $^{n}C_{(n+1)/2}$ if $n$ is odd.For $a = ^{19}C_{p}$,the greatest value is $^{19}C_{9} = ^{19}C_{10} = a$.For $b = ^{20}C_{q}$,the greatest value is $^{20}C_{10} = b$.For $c = ^{21}C_{r}$,the greatest value is $^{21}C_{10} = ^{21}C_{11} = c$.We have $b = ^{20}C_{10} = \frac{20}{10} 	imes ^{19}C_{9} = 2a$.We have $c = ^{21}C_{10} = \frac{21}{11} 	imes ^{20}C_{10} = \frac{21}{11}b = \frac{21}{11}(2a) = \frac{42a}{11}$.Thus,$a : b : c = a : 2a : \frac{42a}{11} = 1 : 2 : \frac{42}{11} = 11 : 22 : 42$.This implies $\frac{a}{11} = \frac{b}{22} = \frac{c}{42}$.

If $a, b,$ and $c$ are the greatest values of $^{19}C_{p}, ^{20}C_{q},$ and $^{21}C_{r}$ respectively,then

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