If A = { x : x text{ is a natural number} },B | vedclass

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(A) Given sets are:$A = \{1, 2, 3, 4, 5, \ldots \}$$B = \{2, 4, 6, 8, \ldots \}$$C = \{1, 3, 5, 7, 9, \ldots \}$$D = \{2, 3, 5, 7, \ldots \}$The inter

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$\varnothing$

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(A) Given sets are:$A = \{1, 2, 3, 4, 5, \ldots \}$$B = \{2, 4, 6, 8, \ldots \}$$C = \{1, 3, 5, 7, 9, \ldots \}$$D = \{2, 3, 5, 7, \ldots \}$The intersection $B \cap C$ represents the set of elements that are common to both $B$ and $C$.Since $B$ contains only even natural numbers and $C$ contains only odd natural numbers,there are no common elements between them.Therefore,$B \cap C = \varnothing$.

If $A = \{ x : x \text{ is a natural number} \}$,$B = \{ x : x \text{ is an even natural number} \}$,$C = \{ x : x \text{ is an odd natural number} \}$ and $D = \{ x : x \text{ is a prime number} \}$,find $B \cap C$.

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