In an $LCR$ series circuit,if ${X_C} < {X_L}$ and ${X_C} > {X_L}$,determine whether the current in the circuit leads or lags the voltage.

  • A
    Current leads voltage when ${X_C} < {X_L}$,and lags when ${X_C} > {X_L}$.
  • B
    Current lags voltage when ${X_C} < {X_L}$,and leads when ${X_C} > {X_L}$.
  • C
    Current leads voltage in both cases.
  • D
    Current lags voltage in both cases.

Explore More

Similar Questions

$A$ sinusoidal voltage of peak value $283 \, V$ and angular frequency $320 \, rad/s$ is applied to a series $LCR$ circuit. Given that $R = 5 \, \Omega$,$L = 25 \, mH$,and $C = 1000 \, \mu F$. The total impedance and the phase difference between the voltage across the source and the current will respectively be:

For the $AC$ circuit shown in the figure,$R = 100 \ k\Omega$ and $C = 100 \ pF$. The phase difference between $V_{\text{in}}$ and $(V_B - V_A)$ is $90^{\circ}$. The input signal frequency is $10^x \ rad/sec$,where $x$ is . . . . . . .

$A$ charged capacitor discharges through a resistance $R$ with time constant $\tau$. The two are now placed in series across an $AC$ source of angular frequency $\omega = \frac{1}{\tau}$. The impedance of the circuit will be

Difficult
View Solution

In an $AC$ circuit,a resistance of $R \, \Omega$ is connected in series with an inductance $L$. If the phase angle between voltage and current is $45^o$,the value of inductive reactance will be:

If $L$ and $R$ are respectively the inductance and resistance,then the dimensions of $\frac{R}{L}$ will be

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo