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(B) Let the first number be $x$ and the second number be $y$.According to the problem,subtracting $25 \%$ of $x$ from $y$ results in $5/6$ of $y$.This

Vedclass · Accepted Answer

$2:3$

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(B) Let the first number be $x$ and the second number be $y$.According to the problem,subtracting $25 \%$ of $x$ from $y$ results in $5/6$ of $y$.This can be written as: $y - (25/100)x = (5/6)y$.Rearranging the terms to group $y$ on one side: $y - (5/6)y = (25/100)x$.Simplifying the left side: $(1/6)y = (1/4)x$.To find the ratio $x:y$,we rearrange the equation: $x/y = (1/6) / (1/4) = 4/6 = 2/3$.Therefore,the ratio of the first number to the second number is $2:3$.

If $25 \%$ of a number is subtracted from a second number,the second number reduces to its $5/6$. What is the ratio of the first number to the second number?

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