If 78 is divided into three parts which are i | vedclass

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(C) The given ratio is $1: \frac{1}{3}: \frac{1}{6}$.To simplify this ratio,multiply each term by the least common multiple $(LCM)$ of the denominator

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$17 \frac{1}{3}$

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(C) The given ratio is $1: \frac{1}{3}: \frac{1}{6}$.To simplify this ratio,multiply each term by the least common multiple $(LCM)$ of the denominators ($3$ and $6$),which is $6$.Ratio $= (1 	imes 6) : (\frac{1}{3} 	imes 6) : (\frac{1}{6} 	imes 6) = 6: 2: 1$.The sum of the parts is $6 + 2 + 1 = 9$.The middle part corresponds to the value $2$.Therefore,the middle part $= \frac{2}{9} 	imes 78 = \frac{2 	imes 26}{3} = \frac{52}{3} = 17 \frac{1}{3}$.

If $78$ is divided into three parts which are in the ratio of $1: \frac{1}{3}: \frac{1}{6},$ the middle part is

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