If Rs. 3000 amounts to Rs. 4320 at compound i | vedclass

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(B) Let the rate of interest be $R\%$ per annum and the time be $n$ years.Given that the amount $A = P(1 + R/100)^n$.Substituting the given values: $4

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$3600$

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(B) Let the rate of interest be $R\%$ per annum and the time be $n$ years.Given that the amount $A = P(1 + R/100)^n$.Substituting the given values: $4320 = 3000(1 + R/100)^n$.Therefore,$(1 + R/100)^n = 4320 / 3000 = 1.44$.We need to find the amount for half the time,i.e.,for $n/2$ years.The required amount is $A' = 3000(1 + R/100)^{n/2}$.Since $(1 + R/100)^n = 1.44$,taking the square root on both sides gives $(1 + R/100)^{n/2} = \sqrt{1.44} = 1.2$.Thus,the required amount $A' = 3000 	imes 1.2 = Rs. 3600$.

If $Rs. 3000$ amounts to $Rs. 4320$ at compound interest in a certain time,then what will $Rs. 3000$ amount to in half of that time (in $Rs.$)?

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