If 64 buckets of water are removed from a cub | vedclass

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(B) The tank is initially full, and after removing water, $1/3$ of the tank remains filled. Therefore, the volume of water removed is $1 - 1/3 = 2/3$

Vedclass · Accepted Answer

$18$

Vedclass · Answer

(B) The tank is initially full, and after removing water, $1/3$ of the tank remains filled. Therefore, the volume of water removed is $1 - 1/3 = 2/3$ of the total volume of the tank.The volume of the cubical tank is $V = (	ext{side})^3 = (1.2\, m)^3 = 1.728\, m^3$.Since $1\, m^3 = 1000\, litres$, the total volume of the tank is $1.728 	imes 1000 = 1728\, litres$.The volume of water removed by $64$ buckets is $2/3$ of the total volume: $V_{	ext{removed}} = 1728 	imes (2/3) = 1152\, litres$.The volume of each bucket is the total removed volume divided by the number of buckets: $V_{	ext{bucket}} = 1152 / 64 = 18\, litres$.

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