If 3/4 of a number is 7 more than 1/6 of the | vedclass

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Question

(D) Let the number be $x$.According to the problem,$\frac{3}{4}x = \frac{1}{6}x + 7$.Subtract $\frac{1}{6}x$ from both sides: $\frac{3}{4}x - \frac{1}

Vedclass · Accepted Answer

$20$

Vedclass · Answer

(D) Let the number be $x$.According to the problem,$\frac{3}{4}x = \frac{1}{6}x + 7$.Subtract $\frac{1}{6}x$ from both sides: $\frac{3}{4}x - \frac{1}{6}x = 7$.The least common multiple of $4$ and $6$ is $12$.So,$\frac{9x - 2x}{12} = 7$.$\frac{7x}{12} = 7$.Multiply both sides by $12$: $7x = 84$.Divide by $7$: $x = 12$.Now,calculate $\frac{5}{3}$ of the number: $\frac{5}{3} 	imes 12 = 5 	imes 4 = 20$.

If $3/4$ of a number is $7$ more than $1/6$ of the number,then $5/3$ of the number is:

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