If frac{a}{b} = frac{1}{2}, then frac{3a + 2b | vedclass

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Question

(NONE) Given that $\frac{a}{b} = \frac{1}{2}.$
To find the value of $\frac{3a + 2b}{3a - 2b},$ divide both the numerator and the denominator by $b$:

Vedclass · Accepted Answer

$-7$

Vedclass · Answer

(NONE) Given that $\frac{a}{b} = \frac{1}{2}.$
To find the value of $\frac{3a + 2b}{3a - 2b},$ divide both the numerator and the denominator by $b$:
$\frac{3a + 2b}{3a - 2b} = \frac{3(\frac{a}{b}) + 2}{3(\frac{a}{b}) - 2}.$
Substitute $\frac{a}{b} = \frac{1}{2}$ into the expression:
$= \frac{3(\frac{1}{2}) + 2}{3(\frac{1}{2}) - 2} = \frac{\frac{3}{2} + 2}{\frac{3}{2} - 2}.$
$= \frac{\frac{3 + 4}{2}}{\frac{3 - 4}{2}} = \frac{\frac{7}{2}}{-\frac{1}{2}}.$
$= \frac{7}{2} 	imes (-\frac{2}{1}) = -7.$

If $\frac{a}{b} = \frac{1}{2},$ then $\frac{3a + 2b}{3a - 2b}$ is equal to

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