(C) Given that $\frac{a}{a+b} = \frac{17}{23}$.If we assume $a = 17$,then $a + b = 23$.From $a + b = 23$,we can find $b$ by substituting $a = 17$:$17

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(C) Given that $\frac{a}{a+b} = \frac{17}{23}$.If we assume $a = 17$,then $a + b = 23$.From $a + b = 23$,we can find $b$ by substituting $a = 17$:$17 + b = 23 \implies b = 23 - 17 = 6$.Now,calculate $a - b$:$a - b = 17 - 6 = 11$.Therefore,the value of $\frac{a+b}{a-b}$ is:$\frac{a+b}{a-b} = \frac{23}{11}$.