If sqrt{5} = 2.236,then what is the value of | vedclass

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(B) Given expression: $\frac{\sqrt{5}}{2} + \frac{5}{3 \sqrt{5}} - \sqrt{45}$First,simplify the terms:$\sqrt{45} = \sqrt{9 	imes 5} = 3 \sqrt{5}$$\fr

Vedclass · Accepted Answer

$-4.845$

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(B) Given expression: $\frac{\sqrt{5}}{2} + \frac{5}{3 \sqrt{5}} - \sqrt{45}$First,simplify the terms:$\sqrt{45} = \sqrt{9 	imes 5} = 3 \sqrt{5}$$\frac{5}{3 \sqrt{5}} = \frac{\sqrt{5} 	imes \sqrt{5}}{3 \sqrt{5}} = \frac{\sqrt{5}}{3}$Substitute these into the expression:$\frac{\sqrt{5}}{2} + \frac{\sqrt{5}}{3} - 3 \sqrt{5}$Take $\sqrt{5}$ as a common factor:$\sqrt{5} \left( \frac{1}{2} + \frac{1}{3} - 3 ight) = \sqrt{5} \left( \frac{3 + 2 - 18}{6} ight) = \sqrt{5} \left( \frac{-13}{6} ight)$Substitute $\sqrt{5} = 2.236$:$2.236 	imes \left( \frac{-13}{6} ight) = 2.236 	imes (-2.1666...) = -4.8447... \approx -4.845$

If $\sqrt{5} = 2.236$,then what is the value of $\frac{\sqrt{5}}{2} + \frac{5}{3 \sqrt{5}} - \sqrt{45}$?

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