If sqrt{frac{x}{169}} = frac{54}{39},then x i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given the equation: $\sqrt{\frac{x}{169}} = \frac{54}{39}$Square both sides of the equation:$\frac{x}{169} = \left(\frac{54}{39}\right)^2$$\frac{x

Vedclass · Accepted Answer

$324$

Vedclass · Answer

(B) Given the equation: $\sqrt{\frac{x}{169}} = \frac{54}{39}$Square both sides of the equation:$\frac{x}{169} = \left(\frac{54}{39}ight)^2$$\frac{x}{169} = \frac{54 	imes 54}{39 	imes 39}$Since $39^2 = 1521$ and $169 = 13^2$,we can simplify the expression:$x = \frac{54 	imes 54}{39 	imes 39} 	imes 169$Note that $169 = 13 	imes 13$ and $39 = 3 	imes 13$,so $\frac{169}{39 	imes 39} = \frac{169}{1521} = \frac{1}{9}$.Therefore,$x = \frac{54 	imes 54}{9} = 6 	imes 54 = 324$.

If $\sqrt{\frac{x}{169}} = \frac{54}{39}$,then $x$ is equal to

Similar Questions

The value of $\frac{1+\sqrt{0.01}}{1-\sqrt{0.1}}$ is nearly equal to

The value of $\sqrt{\frac{(0.03)^{2}+(0.21)^{2}+(0.065)^{2}}{(0.003)^{2}+(0.021)^{2}+(0.0065)^{2}}}$ is

The expression $(2+\sqrt{2})+\frac{1}{(2+\sqrt{2})}+\frac{1}{(2-\sqrt{2})}$ equals

$1.5^{2} \times \sqrt{0.0225} = ?$

The smallest number which is a perfect square and contains $7936$ as a factor is

Vedclass Test Series

Exam Paper Generator

Online Exam Module