If (1 + sin A)(1 + sin B)(1 + sin C) = (1 - s | vedclass

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(B) Let $x = (1 + \sin A)(1 + \sin B)(1 + \sin C)$ and $y = (1 - \sin A)(1 - \sin B)(1 - \sin C)$.Given $x = y$.Multiply both sides by $y$:$xy = y^2$$

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$\pm \cos A \cos B \cos C$

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(B) Let $x = (1 + \sin A)(1 + \sin B)(1 + \sin C)$ and $y = (1 - \sin A)(1 - \sin B)(1 - \sin C)$.Given $x = y$.Multiply both sides by $y$:$xy = y^2$$(1 + \sin A)(1 - \sin A)(1 + \sin B)(1 - \sin B)(1 + \sin C)(1 - \sin C) = y^2$$(1 - \sin^2 A)(1 - \sin^2 B)(1 - \sin^2 C) = y^2$$\cos^2 A \cos^2 B \cos^2 C = y^2$Taking the square root of both sides:$y = \pm \cos A \cos B \cos C$Since $x = y$,each side is equal to $\pm \cos A \cos B \cos C$.

If $(1 + \sin A)(1 + \sin B)(1 + \sin C) = (1 - \sin A)(1 - \sin B)(1 - \sin C)$,then each side is equal to

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