If $\frac{1}{6.198} = 0.16134,$ then the value of $\frac{1}{0.0006198}$ is

$4 \frac{3}{4} + 2 \frac{1}{8} + 7 \frac{1}{4} + 3 \frac{7}{8} + 11 \frac{12}{13} = ?$

If $(\sqrt{3})^{5} \times 9^{2} = 3^{n} \times 3 \sqrt{3}$,then find the value of $n$.

The difference between the numerator and the denominator of a fraction is $5$. If $5$ is added to its denominator,the fraction is decreased by $1 \frac{1}{4}$. Find the value of the fraction.

The value of $\frac{(0.96)^{3}-(0.1)^{3}}{(0.96)^{2}+0.096+(0.1)^{2}}$ is

The value of $\frac{(81)^{3.6} \times (9)^{2.7}}{(81)^{4.2} \times 3}$ is