If 10 men and 15 women complete a piece of wo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let $m$,$w$,and $b$ be the efficiency of a man,a woman,and a boy respectively.
Given: $(10m + 15w) 	imes 8 = (12m + 8w) 	imes 10$
$80m + 120w

Vedclass · Accepted Answer

Quantity $I =$ Quantity $II$

Vedclass · Answer

(C) Let $m$,$w$,and $b$ be the efficiency of a man,a woman,and a boy respectively.
Given: $(10m + 15w) 	imes 8 = (12m + 8w) 	imes 10$
$80m + 120w = 120m + 80w$
$40w = 40m \implies m = w$.
Since a boy is $50\%$ less efficient than a man,$b = 0.5m$,which means $m = 2b$.
Total work = $(10m + 15m) 	imes 8 = 25m 	imes 8 = 200m$ units.
Quantity $I$: $2m + 4w + 18b = 2m + 4m + 9m = 15m$. Time = $200m / 15m = 40/3$ days.
Quantity $II$: $9m + 3w + 6b = 9m + 3m + 3m = 15m$. Time = $200m / 15m = 40/3$ days.
Therefore,Quantity $I =$ Quantity $II$.

Similar Questions

Number of integral values of $a$ for which both roots of the quadratic equation $x^2 - (2a + 3)x + a^2 + 3a = 0$ lie in the interval $(0, 4)$ is:

Solve the given two equations and select the correct answer from the given options.
$I.$ $\frac{9}{\sqrt{x}} + \frac{19}{\sqrt{x}} = \sqrt{x}$
$II.$ $y^{5} - \frac{(28)^{1/2}}{\sqrt{y}} = 0$

Consider the quadratic equation $(c - 5)x^2 - 2cx + (c - 4) = 0$,where $c \ne 5$. Let $S$ be the set of all integral values of $c$ for which one root of the equation lies in the interval $(0, 2)$ and its other root lies in the interval $(2, 3)$. Then the number of elements in $S$ is

If $\alpha$ and $\beta$ are the roots of the equation $x^2 + ax + b = 0$,then the value of $\alpha^3 + \beta^3$ is equal to:

Let one root of $ax^2 + bx + c = 0$,where $a, b, c$ are integers,be $3 + \sqrt{5}$. Then the other root is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module