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(C) Given that $\alpha$ and $\beta$ are the roots of the equation $2x^{2} - 3x + 1 = 0$.From the properties of quadratic equations,the sum of roots $\

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$2x^{2} - 5x + 2 = 0$

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(C) Given that $\alpha$ and $\beta$ are the roots of the equation $2x^{2} - 3x + 1 = 0$.From the properties of quadratic equations,the sum of roots $\alpha + \beta = -(-3)/2 = 3/2$ and the product of roots $\alpha\beta = 1/2$.We need to form a quadratic equation whose roots are $\frac{\alpha}{\beta}$ and $\frac{\beta}{\alpha}$.Let $S$ be the sum of the new roots:$S = \frac{\alpha}{\beta} + \frac{\beta}{\alpha} = \frac{\alpha^{2} + \beta^{2}}{\alpha\beta} = \frac{(\alpha + \beta)^{2} - 2\alpha\beta}{\alpha\beta}$.Substituting the values: $S = \frac{(3/2)^{2} - 2(1/2)}{1/2} = \frac{9/4 - 1}{1/2} = \frac{5/4}{1/2} = 5/2$.Let $P$ be the product of the new roots:$P = \frac{\alpha}{\beta} 	imes \frac{\beta}{\alpha} = 1$.The required quadratic equation is given by $x^{2} - Sx + P = 0$.Substituting $S$ and $P$: $x^{2} - (5/2)x + 1 = 0$.Multiplying by $2$,we get $2x^{2} - 5x + 2 = 0$.

If $\alpha$ and $\beta$ are the roots of the equation $2x^{2} - 3x + 1 = 0$,form an equation whose roots are $\frac{\alpha}{\beta}$ and $\frac{\beta}{\alpha}$.

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