If 5 sin theta = 3,find the numerical value o | vedclass

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(C) Given that $5 \sin 	heta = 3$,so $\sin 	heta = 3/5$.We know that $\cos 	heta = \sqrt{1 - \sin^2 	heta}$.Substituting the value,$\cos 	heta =

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$1/4$

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(C) Given that $5 \sin 	heta = 3$,so $\sin 	heta = 3/5$.We know that $\cos 	heta = \sqrt{1 - \sin^2 	heta}$.Substituting the value,$\cos 	heta = \sqrt{1 - (3/5)^2} = \sqrt{1 - 9/25} = \sqrt{16/25} = 4/5$.Now,$	an 	heta = \frac{\sin 	heta}{\cos 	heta} = \frac{3/5}{4/5} = 3/4$.Also,$\sec 	heta = \frac{1}{\cos 	heta} = 5/4$.Substituting these values into the expression: $\frac{\sec 	heta - 	an 	heta}{\sec 	heta + 	an 	heta} = \frac{5/4 - 3/4}{5/4 + 3/4} = \frac{2/4}{8/4} = 2/8 = 1/4$.

If $5 \sin \theta = 3$,find the numerical value of $\frac{\sec \theta - \tan \theta}{\sec \theta + \tan \theta}$.

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