If x=11, then the value of x^{5}-12 x^{4}+12 | vedclass

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(B) Given $x=11.$We can rewrite the expression $x^{5}-12 x^{4}+12 x^{3}-12 x^{2}+12 x-1$ by substituting $12$ with $(x+1)$ since $x=11$ implies $12=x+

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$10$

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(B) Given $x=11.$We can rewrite the expression $x^{5}-12 x^{4}+12 x^{3}-12 x^{2}+12 x-1$ by substituting $12$ with $(x+1)$ since $x=11$ implies $12=x+1.$$=x^{5}-(x+1)x^{4}+(x+1)x^{3}-(x+1)x^{2}+(x+1)x-1$$=x^{5}-x^{5}-x^{4}+x^{4}+x^{3}-x^{3}-x^{2}+x^{2}+x-1$$=x-1$Substituting $x=11$ into the simplified expression:$=11-1 = 10.$

If $x=11,$ then the value of $x^{5}-12 x^{4}+12 x^{3}-12 x^{2}+12 x-1$ is

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