If log _{10} 50+log _{10} 20=x, then x is equ | vedclass

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(C) Given the equation: $\log _{10} 50+\log _{10} 20=x$Using the logarithmic property $\log_b(m) + \log_b(n) = \log_b(m 	imes n)$:$\log _{10}(50 	im

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$3$

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(C) Given the equation: $\log _{10} 50+\log _{10} 20=x$Using the logarithmic property $\log_b(m) + \log_b(n) = \log_b(m 	imes n)$:$\log _{10}(50 	imes 20)=x$$\log _{10}(1000)=x$Since $1000 = 10^3$,we have:$\log _{10}(10^3)=x$Using the property $\log_b(b^k) = k$:$x=3$

If $\log _{10} 50+\log _{10} 20=x,$ then $x$ is equal to

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