If A(-2, 1),B(1, 0),C(x, 3),and D(1, y) are t | vedclass

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Question

(A) In a parallelogram,the diagonals bisect each other. This means the midpoint of diagonal $AC$ is the same as the midpoint of diagonal $BD$.Midpoint

Vedclass · Accepted Answer

$x=4, y=4$

Vedclass · Answer

(A) In a parallelogram,the diagonals bisect each other. This means the midpoint of diagonal $AC$ is the same as the midpoint of diagonal $BD$.Midpoint of $AC = ((-2+x)/2, (1+3)/2) = ((-2+x)/2, 2)$.Midpoint of $BD = ((1+1)/2, (0+y)/2) = (1, y/2)$.Equating the coordinates of the midpoints:$(-2+x)/2 = 1 \implies -2+x = 2 \implies x = 4$.$y/2 = 2 \implies y = 4$.Therefore,the values are $x=4$ and $y=4$.

If $A(-2, 1)$,$B(1, 0)$,$C(x, 3)$,and $D(1, y)$ are the vertices of a parallelogram $ABCD$,then find the values of $x$ and $y$.

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