If I add 1 to each of the two given numbers,t | vedclass

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(D) Let the two numbers be $x$ and $y$.According to the first condition: $\frac{x+1}{y+1} = \frac{1}{2} \implies 2x + 2 = y + 1 \implies y = 2x + 1$ (

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$35, 71$

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(D) Let the two numbers be $x$ and $y$.According to the first condition: $\frac{x+1}{y+1} = \frac{1}{2} \implies 2x + 2 = y + 1 \implies y = 2x + 1$ (Equation $1$).According to the second condition: $\frac{x-5}{y-5} = \frac{5}{11} \implies 11x - 55 = 5y - 25 \implies 11x - 5y = 30$ (Equation $2$).Substitute $y = 2x + 1$ into Equation $2$: $11x - 5(2x + 1) = 30$.$11x - 10x - 5 = 30 \implies x = 35$.Now,find $y$: $y = 2(35) + 1 = 70 + 1 = 71$.Thus,the numbers are $35$ and $71$.

If $I$ add $1$ to each of the two given numbers,then their ratio is $1:2$. If $I$ subtract $5$ from each of the numbers,the ratio is $5:11$. Find the numbers.

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