If P(x_{1}, 0) and Q(x_{2}, 0) are the points | vedclass

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(B) The distance formula between two points $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ is given by $d = \sqrt{(x_{2}-x_{1})^2 + (y_{2}-y_{1})^2}$.Given poi

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$|x_{1}-x_{2}|$

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(B) The distance formula between two points $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ is given by $d = \sqrt{(x_{2}-x_{1})^2 + (y_{2}-y_{1})^2}$.Given points are $P(x_{1}, 0)$ and $Q(x_{2}, 0)$.Substituting these values into the distance formula:$PQ = \sqrt{(x_{2}-x_{1})^2 + (0-0)^2}$$PQ = \sqrt{(x_{2}-x_{1})^2}$Since the distance must always be non-negative,we take the absolute value:$PQ = |x_{2}-x_{1}| = |x_{1}-x_{2}|$.Therefore,the correct option is $B$.

If $P(x_{1}, 0)$ and $Q(x_{2}, 0)$ are the points on the $X$-axis,then the distance between them $PQ = \ldots$

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