If frac{1}{3} is a zero of p(x) = 3x^2 - 10x | vedclass

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(D) For a quadratic polynomial $p(x) = ax^2 + bx + c$,the product of the zeros is given by $\alpha \cdot \beta = \frac{c}{a}$.Given the polynomial $p(

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$3$

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(D) For a quadratic polynomial $p(x) = ax^2 + bx + c$,the product of the zeros is given by $\alpha \cdot \beta = \frac{c}{a}$.Given the polynomial $p(x) = 3x^2 - 10x + 3$,we have $a = 3$,$b = -10$,and $c = 3$.Let the zeros be $\alpha = \frac{1}{3}$ and $\beta$ be the other zero.Using the product of zeros formula: $\frac{1}{3} \cdot \beta = \frac{3}{3} = 1$.Solving for $\beta$: $\beta = 1 \cdot 3 = 3$.Therefore,the other zero is $3$.

If $\frac{1}{3}$ is a zero of $p(x) = 3x^2 - 10x + 3$,then the other zero is ...........

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